Replace() Help - Printable Version
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Replace() Help by Spunky on 08-19-2006 at 12:17 AM
I searched the forums for this, but the code doesnt seem to quite work in the exact way I want 
I'm making a script that converts a message to a code (in group convos, only people that have the script will recieve the decoded message). I can replace letters, but only as long as it is an exact match (ie it can't have any characters either side of the one I want to replace).
I'm going to use a multi-dimensional array to store the code like so:
code:Thats obviously just an example, but I want to replace ALL "a"s in the message with "XyZ". So I was thinking something like:
myCode = [["a"]["XyZ"],["A"]["xYz"]];
code:inside a For Loop.
tmpMessage = tmpMessage.replace(myCode[0][0],myCode[0][1]);
I know the code seems pointless, but me and my friend usually have group conversations and still talk in a seperate window as well so the other participants don't have a clue what we're talking about.
RE: Replace() Help by Silentdragon on 08-19-2006 at 12:36 AM
code:
var myCode = [ [new RegExp("a","g"),"XyZ"],[new RegExp("A","g"),"xYz"] ];
tmpMessage = tmpMessage.replace(myCode[0][0],myCode[0][1]);
tmpMessage = tmpMessage.replace(myCode[1][0],myCode[1][1]);
1. You made your arrays wrong [ ["Stuff","Stuff2"], ["Stuff3","Stuff4"] ] Thats how to make a multidimensional
2. For replace you need either /texttofind/options or a RegExp object for the first argument.
RE: Replace() Help by Spunky on 08-19-2006 at 12:38 AM
Ok, I knew I did it different before lol 
Whats the "new RegExp" part do then?
RE: Replace() Help by Silentdragon on 08-19-2006 at 12:44 AM
it creates a RegExp object for the replace function
although a better way would be to do this in the for loop
var RegEx = new RegExp(myCode[i][0],"g");
tmpMessage = tmpMessage.replace(RegEx,myCode[i][1]);
so you don't need to make a new RegExp object for each array value.