Help again with php - Printable Version
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Help again with php by YottabyteWizard on 08-09-2007 at 08:21 AM
Sorry to bother you again guys... but I really need to have this working for tomorrow.
The options of a select box are gathered from a table of mysql. And when an option is selected, copy the value of it to a text input.
The query is saved into a variable, but I need to get a certain row information from it... and I don't know how. I already went to php.net and other websites, but cant find the answer.
I currently have this:
code:
<html><head>
<script language="javascript">
function select(id) {
document.forma.docname.value=
}
</script>
</head><body>
<?php
require ('connect.php');
?>
<form name="forma">
Medicamento: <br>
<select name="medica" size=5 onselect="(select(this))";>
<?php
$db['query'] = mysql_query('SELECT * FROM doctores');
while ($db['process'] = mysql_fetch_assoc($db['query'])) {
echo ('<option value="'.$db["process"]["id"].'">'.$db["process"]["nombre"].'</option>');
}
mysql_close();
?>
</select>
<input type=text style="width:100px;" name="docname"><br>
</form>
</body></html>
Obviously the javascript part wont work, im stuck there. Any ideas?
Any help will be greatly appreciated.
RE: Help again with php by matty on 08-09-2007 at 01:36 PM
If you are trying to get the value of the currently selected option from a Select box you need to use this
code:
getId('medica').options[getId('medica').selectedIndex].value;
function getId(id) { return document.getElementById(id); }