Hi guys forum!
I wonder if I have conditions to appear offline to one or a few contacts WLM 2009

already gave me the hint to block all contacts that do not want to see my status, and show me online just for the contact one I want.

so far so good, but if I block those contacts, can not leave messages off line for me

I envy the WLM 2011 because it has the function, invisible to that person.
I love the WLM 2009 and want to keep it installed.

I'd like you to help me give me an alternative to this function that exists in WLM 2011 and what is missing in WLM 2009.

thanks

There isn't a way to just appear offline to certain people in WLM 2009.

You outlined your only options already....either upgrade to 2011 and get the feature you want, or stay on 2009 and stick with either blocking them, or appearing offline to everyone

Some patch, script or other program that knows someone that can offer this kind of function?

This function might come in Messenger Plus! 5? and be enabled in WLM 2009?

This feature is not possible using Plus! Unfortunately, WLM sends your status to a server. Then other users request your status. As WLM 2011 uses a different protocol, it can specify that user x should get the status "offline". Plus! cannot trick WLM 2009 into sending information in the same way. The server would reject the message as it wouldn't understand it (because it uses the older protocol and doesn't recognize the new command)

This is a very basic description of what happens

Ok! But at least have as I get offline messages from my blocked contact?
Have any way?

WLM2011 will allow contacts to send you a message even if you have them blocked they just won't see your status.

erm....
you shold try to read this article... i shows how to appear offline for some users...

cheers!!

matty said: "WLM2011 will allow contacts to send you a message even if you have them blocked they just won't see your status."

bambapill...

guys I wonder if you has as for WLM 2009
I refer to the WLM 2009

nobody more intelligent able to give a good guess to solve this?

quote:

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Originally posted by Dartagnan
nobody more intelligent able to give a good guess to solve this?

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