Shoutbox

quote:

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Originally posted by Chrono
i see you solved 14!/(14-3)!*3!, but why? I'd like to know (Smilie)

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oh

you get the 14 by doing 11+3 and you get the 3 by doing one less than the amount of X's
so you get C(14,3) which = 14!/(14-3)!*3!

so its something like
n = result + (amount - 1)
r = amount - 1
C(n, r)


i think... o;

hmm dt doing math.. interesting ;o
hotness++;

quote:

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Originally posted by John Anderton
hmm dt doing math.. interesting ;o
hotness++;

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and ja didnt want to be apart of the mathness :--o

I'd appreciate it if some one would explain why 5/12 of answer ( a ) isn't correct..

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Originally posted by foaly

I'd appreciate it if some one would explain why 5/12 of answer ( a ) isn't correct..

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Integers ?

quote:

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Originally posted by Jhrono

quote:

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Originally posted by foaly

I'd appreciate it if some one would explain why 5/12 of answer ( a ) isn't correct..

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Integers ?

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nvm just realizing that x1=0 has less possibilities then x1=3