Shoutbox

How do I use a property

i.e.:

I have the Debug object, and I want to popup the Debugging Window (being it activated)
How do I use DebuggingWindowVisible?

Post a sample code or somehting please?

Thanks

Debug.DebuggingWindowVisible = false;

getting:
var test = Debug.DebuggingWindowVisible;

setting:
Debug.DebuggingWindowVisible = true;