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RE: Maths Help (for the know alls :P)
the answer is:
- total numbers = 4 possible letters: a, b, c, d
- number of changes (value of the letter) for unit 0 in "adbca" = 0 => 0 * 4 ^ 0
- number of changes (value of the letter) for unit 1 in "adbca" = 2 => 2 * 4 ^ 1
- number of changes (value of the letter) for unit 2 in "adbca" = 1 => 1 * 4 ^ 2
- number of changes (value of the letter) for unit 3 in "adbca" = 3 => 3 * 4 ^ 3
- number of changes (value of the letter) for unit 4 in "adbca" = 0 => 0 * 4 ^ 4
- 0*4^4 + 3*4^3 + 1*4^2 + 2*4^1 + 0*4^0 = 216
=> position or row number 217
.-= A 'frrrrrrrituurrr' for Wacky =-. | 
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