Shoutbox

I don't know if you're doing this, but if there are repeated letters there is a formula for it.

eg. AAABB

n = total letters = 5
x = no. of As      = 3
y = no. of Bs      = 2

number of permutations formula = n! divided by (x! * y!) where x and y are the number of times the repeated letters occur.

n! = 5*4*3*2*1 = 120
x! = 3*2*1 = 6
y! = 2*1  = 2

120/(6*2) = 120/12 = 10 permutations

Don't know if you need that and sorry if i didn't explain it well enough, but it might come in handy.

Just to explain a bit more, say you had the word AAAABBBCCD

n = 10 (total letters)
w = 4 (number of As)
x = 3 (number of Bs)
y = 2 (number of Cs)
z = 1 (number of Ds)

formula = n! / (w!*x!*y!*z!)

             = 10! / 4!*3!*2!*1!

             = 3628800 / 288

             = 12600 permutations