Shoutbox

quote:

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Originally posted by Plik
Probability of it happening just once = 12/25 = 48%

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(i think )

P(A)=0,6
P(B)=0,6

P(AvB) = P(A)+P(B) - 2*P(A^B) = 0,6 + 0,6 - 2*0,36 =1.2 - 0,72 = 0,48 = 48%

i think that's how you do it :-/ (that would be the probability of getting it JUST on one try (not on AT LEATS one try), it's funny how you can know really advanced maths and forget about such simple stuff :P