Shoutbox

quote:

---

Originally posted by andrewdodd13
Well... the square root of x^2 1/x^2 is just x + 1/x isn't it?

---

No it isn't...

The square root of x * x = x... So the square root of x * x + a, where a > 0, is greater then x... Right?

When x > 0, 1 / (x * x) > 0, so the square root will be greater then x. You see?

The integral of that formula is hard to find... and it's been a while since I have been integrating formulas...