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RE: Calculus integration problem. please help.
never did this type of problem b4, and substitution technique doesnt seem to work for it so maybe that's how it goes:
we know that :
(x^2 + 1/x^2)^1/2 = (x + 1/x)
so we are left with:
S (x + 1/x) (x + 1/x)
multiply them we get:
S (x^2 + 2 + x^-2)
so the answer is:
1/3 x^3 + 2x - 1/x
Again Im not sure and didnt look for other ways to solve it, but who knows maybe I'm right
This post was edited on 10-17-2006 at 09:28 PM by s7a5.
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