Shoutbox

I don't have enough time to actually to solve it atm, but I think I know how I would attempt it.

int*(x + 1/x) * int*((x^2 + 1/x^2)^(1/2))

As I'm sure someone pointed out earlier.

1/x^2 indeed is 1/x. Try it with a number and put it in your calculator. Insttead of agruing about the square root part, why don't just fuse the expressions under the root to one? Might be more complicated, but at least you can't have different opinions then.

x^2 + 1/x^2 = (x^2 + 1) / x^2

Now of course, we will have the fun of realising there are no x outside the parenthesis, so we will have to divide and get some funky number, which I'm certaninly not arsed to do atm.

EDIT: As I wasn't sure about the thing you are arguing on, I decided just to comment it. Shouldn't it be possible just to take the square root of x^2, which is x, and the root of 1/x^2, which is 1/x, and then write it as x + 1/x and then int* that part?