Shoutbox

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Originally posted by Jhrono

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Originally posted by -dt-

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Originally posted by Adeptus

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Originally posted by -dt-
i have notes on how to do them if they are >= something but (Smilie) I've never encountered a <= one so I'm unsure of how to solve it.

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It seems to me if you know how to solve it for x1 >= 5 (which you are implying you do), then you could subtract the number of those solutions from the total number of solutions and get the answer you want....

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oh thanks I never thought of that

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Will that work? Remember that the procedure you are aware of also includes the = solutions so, those will be common. By Adeptus method, you'll obtain the < solutions. Or am I looking at this in a wrong way?

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if i change it to >= 4 and then subtract it, i should get the same as <= 4, shouldnt i?

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OH i see what you're saying... hm... maybe if i just do > 4 *looks for his notes*

oh wait i would have to subtract > 6 to get the < 4 stuff right? or am i just confusing myself more....

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oh *reads Adeptus's post below* *fixes what hes done*