quote:
Originally posted by Jhrono
Will that work? Remember that the procedure you are aware of also includes the = solutions so, those will be common. By Adeptus method, you'll obtain the < solutions. Or am I looking at this in a wrong way?
The reason why my "method" was fine is because in a diophantine equation, all variables are whole integers. Thus, if you remove everything >= 5, what remains will be <= 4 -- because there obviously are no whole integers between 4 and 5.
