interop call open - Printable Version
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interop call open by roxy_dany22 on 11-12-2007 at 03:14 PM
hi!(i'm italian..sorry 4 my bad english)
i've read in one topic to call this function to execute a file:
code:
Interop.Call("shell32.dll", "ShellExecuteW", null, "open", "C:app.exe", "param1 param2", "", SW_SHOWDEFAULT)
but it says that SW_SHOWDEFAULT is not defined...what shall i do?
RE: interop call open by Spunky on 11-12-2007 at 03:45 PM
Constants are not not defined so you need to find the value of SW_SHOWDEFAULT and set it...
I think it's 10 so either declare it globally or just change SW_SHOWDEFAULT to 10.
RE: interop call open by Matti on 11-12-2007 at 05:15 PM
You may also want to change "C:app.exe" to "C:\\app.exe". And I don't know if you want "param1 param2" sent to that application, maybe you need to have a look at those too? 