python functions wft - Printable Version
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python functions wft by Jarrod on 08-02-2008 at 11:58 PM
i'm trying to write a python function which takes the string "s" and turns in a string or integer from an English representation, for example:
five six nine
will return
569
i wrote all the code to do it, and it looks like this
code:now when i turn it into a function is should look like this
s = raw_input("what is the string")
s = s.replace('one','1')
s = s.replace('two','2')
s = s.replace('three','3')
s = s.replace('four','4')
s = s.replace('five','5')
s = s.replace('six','6')
s = s.replace('seven','7')
s = s.replace('eight','8')
s = s.replace('nine','9')
s = s.replace('zero','0')
s = s.replace(' ','')
s = s.strip()
s = s
print s
code:but my return does not work can someone explain the technicalities of that to me?
s = raw_input("what is the string")
def words2number(s):
while 1:
s = s.replace('one','1')
s = s.replace('two','2')
s = s.replace('three','3')
s = s.replace('four','4')
s = s.replace('five','5')
s = s.replace('six','6')
s = s.replace('seven','7')
s = s.replace('eight','8')
s = s.replace('nine','9')
s = s.replace('zero','0')
s = .replace(' ','')
s = s.strip()
s = s
return s
words2number(s)
RE: python functions wft by segosa on 08-03-2008 at 01:37 AM
I don't know python at all but why is the function inside a while loop that'll continue forever?
RE: python functions wft by Jarrod on 08-03-2008 at 01:53 AM
why not?
the return will act if a break if it works correctly anyway
quote:z = words2number(s)
Originally posted by Jarrod
code:
s = raw_input("what is the string")
def words2number(s):
while 1:
s = s.replace('one','1')
s = s.replace('two','2')
s = s.replace('three','3')
s = s.replace('four','4')
s = s.replace('five','5')
s = s.replace('six','6')
s = s.replace('seven','7')
s = s.replace('eight','8')
s = s.replace('nine','9')
s = s.replace('zero','0')
s = .replace(' ','')
s = s.strip()
s = s
return s
words2number(s)
print z
stop spamming you 2
RE: python functions wft by ShawnZ on 08-03-2008 at 10:01 AM
quote:
Originally posted by Jarrod
why not?
because a loop that goes forever... doesn't end?
RE: python functions wft by Mnjul on 08-03-2008 at 10:07 AM
There's a return inside the loop so the loop breaks. However that loop statement is indeed necessary.. you don't need the "while 1:", Jarrod 
And you're missing an s here:
s = .replace(' ','')
RE: python functions wft by Jarrod on 08-03-2008 at 11:14 AM
i am missing an s the return does break the loop and tbh the loop isn't necessary but it's there to make sure, i did it without the loop in the end by as i said above z = words2numbers(s)
and ShawnZ didn't you read my post the return breaks the loop
RE: python functions wft by foaly on 08-03-2008 at 11:54 AM
quote:should break the loop....if it doesn't the program will probably crash...
Originally posted by Jarrod
and ShawnZ didn't you read my post the return breaks the loop