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[?] "Dynamic" RegExp replace...
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Matti
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RE: [?] "Dynamic" RegExp replace...
The reason why your version won't work is because regexp.$1 is evaluated once when that line is run.

However, you can still do this without a for-loop and lots of replace calls. JScript allows you to pass a function as second parameter for replace, whose return value will be used as replacement for each match. When using regular expressions, it'll even give you all the good stuff through the function's arguments!
Javascript code:
var output = input.replace(regex, function(match, $1) {
    // You could do literally anything here!
    return ($1 in some_variables) ? some_variables[$1] : '';
});

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08-17-2011 02:22 PM
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Messages In This Thread
[?] "Dynamic" RegExp replace... - by whiz on 08-16-2011 at 05:57 PM
RE: [?] "Dynamic" RegExp replace... - by Eljay on 08-16-2011 at 06:19 PM
RE: [?] "Dynamic" RegExp replace... - by whiz on 08-16-2011 at 06:54 PM
RE: [?] "Dynamic" RegExp replace... - by Matti on 08-17-2011 at 02:22 PM
RE: [?] "Dynamic" RegExp replace... - by whiz on 08-17-2011 at 06:20 PM


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