Shoutbox

quote:

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Originally posted by CookieRevised
Easier or harder is irrelevant. The thing would still be in the exact same state. The center of gravity has got nothing todo in all of this.

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So if we would double the weight at the left (and only effecting the center of the gravity) it wouldn't change anything?

I'm still not sure if you are serious or are just trying to troll us with your Zeno style logic...

You are right though...:

if  (cos A)*(mass of chain above BC) > (cos G)*(mass of chain above AC), it will fall to the left.
if (cos A)*(mass of chain above BC) < (cos G)*(mass of chain above AC), to the right.

lets assume the mass of the chain is equal to the distance...
cos A = CD / BC  -> CD = cos A * BC
cos G = CD / AC -> CD = cos G * AC
-->
cos A * BC = cos G * AC
so it will balance...

The way you came to your conclusion just seems wrong