quote:
Originally posted by vaccination
No, because you are you are adding additional forces in different directions that aren't there in the original system.
Forces which cancel eachother out!!!!!!!!
quote:
Originally posted by vaccination
For example, the horizontal and vertical forces exerted by that chain create two new component forces acting down and towards the centre(which would acts against the slopes).
You just proved my point....
"acting down and
towards the centre"...
aka: they cancel eachother out as they are in opposite direction and there is only a downward net force going from the center of mass strait down. Any extra force going strait down on the center of mass does not have any influence on the movement of that mass, in any system, frictionless, vacuum, whatever. And since the center of mass has therefore NOT moved an inch in the horizontal plane, not a tiny tiny fraction, it is still exactly above the same point as it was before and therefore that extra chain has got NO influence at all on the movement of the top chain.
quote:
Originally posted by vaccination
quote:
Originally posted by CookieRevised
They _all_ math exactly the criteria...
No they don't. The first 3 of your diagrams contain two slopes at the same angle as each other, Sam's criteria is that one be "flatter" (at a smaller angle to the horizontal) than a "steeper" slope (at a greater angle to the horizontal). Maybe *you* should look at it again.
Sorry, but ever heared of limits and delta values?
State what you want, the picture shows exactly what the limits of the system are and is according every criteria SonicSam's teacher has given.
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