RE: Calculus integration problem. please help. Wow! It appears that everyone is getting something different. Here is what I did. I used substitution and realized that the 1/x^2 can be rewritten as 1x^-2. Integration: (x + 1/x) (sqrroot(x^2+x^-2)) dx u = x^2+x^-2 dx du = 2x - 2x^-1 dx (1/2)du =...