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Trigonometry Problem - Please help
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Shervin.B
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O.P. Trigonometry Problem - Please help
I had this problem in a test and I didn't know how to do it. I'm in Year 9


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11-15-2005 08:15 AM
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Ash_
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RE: Trigonometry Problem - Please help
it's right angle trigonomotry.

this example uses Cosine (Adjacent and Hypotinuse)

so you basically put in the calculator Cos(-1) (a/3a)

understand?
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11-15-2005 08:18 AM
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Shervin.B
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O.P. RE: Trigonometry Problem - Please help
ahh yess Thankyou! I had a mind blank in the test. I hope i did well... it was our yearlies. but i don't have an A on my calculator.

This post was edited on 11-15-2005 at 05:43 PM by Fraisie.
11-15-2005 08:19 AM
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ipab
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RE: Trigonometry Problem - Please help
perhaps this will aid him in remembering it better

soh cah toa

sine=opposite/hypotenuse
cosine=adjascent/hypotenuse
tangent=opposite/adjascent

hope this helps :).

the A is just a variable. It cancels out of this equation.

This post was edited on 11-15-2005 at 08:23 AM by ipab.
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11-15-2005 08:21 AM
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John Anderton
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RE: Trigonometry Problem - Please help
quote:
Originally posted by ipab
perhaps this will aid him in remembering it better

soh cah toa

sine=opposite/hypotenuse
cosine=adjascent/hypotenuse
tangent=opposite/adjascent

hope this helps [Image: msn_happy.gif].

the A is just a variable. It cancels out of this equation.
I have a better way ... well i had two but i cant remember one as i never used it ....

OAO
HHA

Sine cosine Tan

And we all know the other 3 are reciprocals of the first three ;)

Say it like "O-A-O upon (divided by) H-H-A"

Hence Sine = O/H; Cosine = A/H and Tan (Tangent) = O/A

So obviously for Cosecant, Secant and Cotangent read it the other way round (ie the bottom 3 first .....) or just remember Cosecant = 1/Sine
:D


Sin (2x) = 2 Sin (x) . Cos (x)
tanh^(-1) (x) = (1/2) * log [(1+x)/(1-x)]


</trigonometry mode>

8-) *-) :$
:P :P

This post was edited on 11-15-2005 at 05:17 PM by John Anderton.
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11-15-2005 09:43 AM
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ddunk
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RE: Trigonometry Problem - Please help
While we're at it, a/3a = 1/3
cos^-1(1/3) = 70.5288 = x

This post was edited on 11-15-2005 at 03:09 PM by ddunk.
11-15-2005 03:07 PM
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Rubber Stamp
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RE: Trigonometry Problem - Please help
can u calculators at school? thats cool, we cant.
11-15-2005 05:30 PM
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John Anderton
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RE: Trigonometry Problem - Please help
quote:
Originally posted by Rubber Stamp
can u calculators at school? thats cool, we cant.
Hehe i know ..... thats why the students in our schools are good at maths (thats what i have heard)
What i have heard is that usually students from india score well in their maths sat's

I can use a calculator now that im in engineering :banana:
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11-15-2005 05:42 PM
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user27089
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RE: Trigonometry Problem - Please help
We have always been allowed to use a calculator, only on questions that are caculator-friendly though ;).
11-15-2005 05:47 PM
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John Anderton
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RE: Trigonometry Problem - Please help
quote:
Originally posted by traxor
We have always been allowed to use a calculator, only on questions that are caculator-friendly though ;).
The thing is that we are used to having non calculator sums (always having the angle as 0, 30, 45 or 90 .... or well .... continue that series in every quadrant) so when if we goto engineering (like i did) we have a calculator in our hands then we work faster cause we use our brains as well for the simple calculations in that series ..... but people say not to get too dependent on it .... cause then you become slower at mental mathematics cause by the end of 12th grade the best students are so good that they can tell you the answers to integration which will take 2 pages without writing a word (mental calculus) ..... pfft ..... now im lazy i do my integration on my calculator so i aint as good at mental calculus as i was then :P


quote:
Originally posted by Shervin.B
but i don't have an A on my calculator.
Which calculator are you on Shervin ??? Higher scientific calculators can directly solve 1 variable equations. For 2 and 3 variable equations there are modes .... my calculator doesnt go higher than that.
Im using a Casio fx-991MS :D

This post was edited on 11-15-2005 at 06:01 PM by John Anderton.
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11-15-2005 05:58 PM
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