Shoutbox

Whatever you send, you must send it as a string (since sResult is defined as a string in the plugin API in VB in the ParseCommand procedure)... So convert your integers to a string and use that as the sResult variable to send back...

You could use the poor-mans method:
your integers:
I1 = 1234
I2 = -4789
I3 = 45
the string you send: "1234,-4789,45"
eg: sResult = Chr$(nCCNotify) & "smvpg" & "1234,-4789,45"

Using the ReceiveNotify procedure, sText will contain "1234,-4789,45". Thus, you interpret it again by splitting it up, using the comma as delimeter.


Or the smart advanced method:
(allows you to send/recieve _a lot_ of integers! Per character, you normally could send, you have 1 integer. Because a character is actually always 2 bytes, the same as an integer...)

your integers are the same as above,

Since an integer (or whatever) is stored as sequences of bytes in memory and strings are stored just the same way, you can interpret each integer as a wide character of a string. Because an integer consist of two bytes and a wide string character also consist of two bytes. Thus the string, using the example integers above, would consist of only 3 wide characters (=6 bytes, this in contrast to the first method where your string consists of 26 bytes): ChrW$(1234) & ChrW$(-4789) & ChrW$(45).
eg: sResult = Chr$(nCCNotify) & "smvpg" & ChrW$(1234) & ChrW$(-4789) & ChrW$(45)

Using the ReceiveNotify procedure, sText will contain ChrW$(1234) & ChrW$(-4789) & ChrW$(45). Thus, you interpret it again by getting the wide characters one by one:
Dim I as Integer
For T=1 To Len(therecievedstring)
  I = AscW(Mid$(therecievedstring, T, 1))
Next T