I'll do it for ya. Took physics last year. just hold on tho
Basically, what I can see is that there is two equations:
(let's hope they're right!)
8t=sin(Θ; )Vt + 12
2=cos(Θ )Vt
solve for the minimization for V
hmm dodgy theta's
anyways, I solved for t in each equation, then set them equal to each other.
V = 8/(6cos(
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
) + sin(
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
) )
graphing this gives
and differentiating
dV/d
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
= -8*(-6sin(
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
)+cos(
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
))/(6cos(
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
)+sin(
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
))^2
solving for critical points gives
![[Image: theta.bmp]](http://myweb.dal.ca/ad376495/theta.bmp)
= arctan(1/6) or or .0029 degrees. The corresponding velocity comes out to be 1.315 m/s
ya, ya its different, but I might have messed up the equations at the beginning