Shoutbox

quote:

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Originally posted by .Roy
It will lower the chance, and I already know that if you get it 3 times in a row Its (1/10*1/10*1/10) Which SHOULD be a lower percentage then getting it in 3 random points of the draw.

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There's a slight difference though, if i understood your post correctly .
The probability of getting it 3 times in a row is indeed (1/10)^3. BUT, that's considering that you DON'T CARE about what you get in the other 2 tries. So, the probability is, being "A" what you want to get: P(getting A)^3 * P(getting whatever)^2 = (1/10)^3 * 1^2 = (1/10)^3 (Yes, the probability of getting it 3 times in a row or getting it AT LEAST 3 times in random points is exactly the same for that matter ).

Now in the other question they ask you to calculate the probability of getting A 3 times OUT OF 5 (meaning that you have to get EXACTLY 3 times "A", not AT LEAST 3 times. So in the other 2 tries you MUST get, let's say, "B" which will obviously lower the possibility. So the probability is: P(getting A)^3*P(getting B)^2 = (1/10)^3*(9/10)^2