What happened to the Messenger Plus! forums on msghelp.net?
Shoutbox » MsgHelp Archive » General » General Chit Chat » How do you call this type of math...

How do you call this type of math...
Author: Message:
.Roy
Veteran Member
*****

Avatar

Posts: 1526
Reputation: 11
20 / Male / –
Joined: Aug 2004
O.P. How do you call this type of math...
I dont know the name in english so ill explain it.

Its when you have an equation and you have to prove its true for every n. for n=positive interger.

so u put in the equation n+1 and then u prove it that way...


So what is this type of math called??

----------

Its like geometry on a graph (x,y).... Also dont know the name.

This post was edited on 11-08-2006 at 03:44 PM by .Roy.
11-08-2006 03:42 PM
Profile PM Web Find Quote Report
John Anderton
Elite Member
*****

Avatar

Posts: 3908
Reputation: 80
37 / Male / Flag
Joined: Nov 2004
Status: Away
RE: How do you call this type of math...
quote:
Originally posted by .Roy
Its when you have an equation and you have to prove its true for every n. for n=positive interger.

so u put in the equation n+1 and then u prove it that way...
Induction.
[

KarunAB.com
]

[img]http://gamercards.exophase.com/459422.png[
/img]
11-08-2006 03:45 PM
Profile E-Mail PM Web Find Quote Report
.Roy
Veteran Member
*****

Avatar

Posts: 1526
Reputation: 11
20 / Male / –
Joined: Aug 2004
O.P. RE: How do you call this type of math...
Also what do you call it in calculus when you make something from
f( x ) to f( x ) '

This post was edited on 11-08-2006 at 04:00 PM by .Roy.
11-08-2006 03:54 PM
Profile PM Web Find Quote Report
Jesus
Scripting Contest Winner
****

Avatar
Koffie, my cat ;)

Posts: 623
Reputation: 15
38 / Male / Flag
Joined: Jul 2005
RE: RE: How do you call this type of math...
quote:
Originally posted by .Roy
Also what do you call it in calculus when you make something from
f( x ) to f( x ) '


quote:
derived function - the result of mathematical differentiation; the instantaneous change of one quantity relative to another; df(x)/dx

This post was edited on 11-08-2006 at 04:20 PM by Jesus.
11-08-2006 04:20 PM
Profile PM Find Quote Report
qgroessl
Veteran Member
*****


Posts: 1615
Reputation: 22
33 / – / Flag
Joined: Jul 2005
Status: Away
RE: How do you call this type of math...
quote:
Originally posted by .Roy
f( x ) to f( x )

We just call Function of X or... F of X for short... (derived function is probably the mathematical term for it though.

:p... okay... so I didn't see the '  lol...

This post was edited on 11-09-2006 at 12:16 AM by qgroessl.
11-08-2006 05:10 PM
Profile PM Find Quote Report
CookieRevised
Elite Member
*****

Avatar

Posts: 15517
Reputation: 173
– / Male / Flag
Joined: Jul 2003
Status: Away
RE: How do you call this type of math...
quote:
Originally posted by .Roy
I dont know the name in english so ill explain it.

Its when you have an equation and you have to prove its true for every n. for n=positive interger.

so u put in the equation n+1 and then u prove it that way...


So what is this type of math called??
I dunno what it is called in English... Though I fail to see how putting n+1 in the equation would proof such an equation....

You just need to solve the equation in such a way that n is on the left of the equation and something else is on the right of the equation, where the equation is actually a "greater than" sign...

eg: solve it so you come to something like "n > 0".
eg: is n*8 > n always true if n=postive integer? yes, proof:
1) n*8 > n
2) (n*8)-n > n-n
3) n*7 > 0
4) n*7/7 > 0/7
5) n > 0

if that is what you meant


quote:
Originally posted by UTI
quote:
Originally posted by .Roy
f( x ) to f( x )'

We just call Function of X or... F of X for short... (derived function is probably the mathematical term for it though.
function of X is correct for f(x)... but note the ' after f(x), which means f(x)' is the derived function of x.

The ' wasn't a typo in his post...

;)

This post was edited on 11-08-2006 at 07:16 PM by CookieRevised.
.-= A 'frrrrrrrituurrr' for Wacky =-.
11-08-2006 07:03 PM
Profile PM Find Quote Report
.Roy
Veteran Member
*****

Avatar

Posts: 1526
Reputation: 11
20 / Male / –
Joined: Aug 2004
O.P. RE: How do you call this type of math...
quote:
Originally posted by CookieRevised
function of X is correct for f(x)... but note the ' after f(x), which means f(x)' is the derived function of x.

The ' wasn't a typo in his post...

;)

I didnt describe what i meant enough...

John anderton got it though :O.

I mean to prove for example an equation is true, you first "say its true" and then prove its true for n+1. And then you find a way to insert the true statement in the new equation and u get something that is true for example n^2>0 and u know n^2 is always positive so...
11-08-2006 08:07 PM
Profile PM Web Find Quote Report
Voldemort
Veteran Member
*****

Avatar

Posts: 3504
Reputation: 49
– / – / Flag
Joined: Jul 2005
Status: Away
RE: How do you call this type of math...
didnt f(x )' mean everything out of x?

This post was edited on 11-09-2006 at 12:00 AM by Voldemort.
*All posts are a purely speculative hypothesis based on abstract reasoning.
Not my daughter, you bitch!
[Image: ico-mollytrix16.gif]
11-09-2006 12:00 AM
Profile E-Mail PM Find Quote Report
Rubber Stamp
Senior Member
****

Avatar
It Was Never Random

Posts: 587
Reputation: 14
35 / Male / –
Joined: May 2004
RE: How do you call this type of math...
Voldemort, what you mean is compliment, it is used in set theory and related chapters like probabilty and stuff. it is also denoted by x^c or x bar. but in calculus, ' means derived function of the given function.
answer to first query : Mathematical Induction
answer to second query: Differentiation.
11-10-2006 01:35 PM
Profile E-Mail PM Find Quote Report
Vilkku
Veteran Member
*****

Avatar

Posts: 1411
Reputation: 27
36 / Male / Flag
Joined: Mar 2003
RE: How do you call this type of math...
Cookie: In Dutch it's called "inductie" (used Wikipedia to get it).
It's a special kind of math, so I suggest you don't start doubting :P

Example:
Show that 1+2+3+...+n = (n(n+1))/2 is true when n is a positive integer.

You would solve that this way:
1. n=1, both sides equal 1, so it's true.
2. Assume that it is true for n=k, so if it is true for k+1 we have prooven it's always true.
3. We prooved that 1+2+3+...+k is (k(k+1))/2 is the first step, so we can replace the set of numbers with that expression. We get
(k(k+1))/2 + (k+1) = ((k+1)(k+2))/2
Then you solve the right and left side separately, in this both are
(1/2)k^2 +  (3/2)k + 1
We have now prooven it's true using induction :)

This post was edited on 11-11-2006 at 12:41 PM by Vilkku.
[Image: signature.php]
11-11-2006 12:40 PM
Profile E-Mail PM Web Find Quote Report
« Next Oldest Return to Top Next Newest »


Threaded Mode | Linear Mode
View a Printable Version
Send this Thread to a Friend
Subscribe | Add to Favorites
Rate This Thread:

Forum Jump:

Forum Rules:
You cannot post new threads
You cannot post replies
You cannot post attachments
You can edit your posts
HTML is Off
myCode is On
Smilies are On
[img] Code is On