Shoutbox

hehe just use the green formula I put and ignore what i wrote correcting Dempsy...

          n= [(n-1)-(n-2)+6] + (n-1)

And this does work. As for DDunk saying 0 is the first number that also works with this equation.

If I used the 1st figure (3) and substitute all of the blue numbers below into my equation, this is what results:

n=3
(n-1)=0
(n-2)=3 (I got this answer because it must be the opposite of the 3 ie the system is a quadratic)

      therefore n= (0-3+6)+0
                        =3

**********
 
Actual value of n          -2         -1         0           1           2        3             4              5

Actual number value      12         3          0            3         12       27          48           75
                                 
No.s used in example   (n-3)     (n-2)    (n-1)        (n)        (n+1)      (n+2)      (n+3)     (n+4)