| PHP/MySQL help |
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lordy
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O.P. PHP/MySQL help
I'm creating a MySQL database for my dad so he can catalogue his huge collection of DVD's and CD's etc. I'm doing it cause i want to learn PHP and mySQL and stuff, so i figured I may as well do something useful with it while im going. It's being accessed using PHP via our webrowser over our home network. atm i have it so the page displays all entries in the database.
My questions are: How do you make a webpage in which you can easily add a new entry into the database (ie. add a new DVD/CD), using a form, so its easier for my dad to add new dvd's.
and how do i make a search form so my dad can search for a particular DVD within the database?
Im not sure if i've given enough information here... If you need something else then let me know. and dont be worried about talking n00bish to me cos im a n00b at this sort of stuff  (hence why i am trying to learn) |
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| 11-10-2005 12:04 PM |
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Dempsey
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RE: PHP/MySQL help
well to add stuff you need a form which will send the results to a php page which will then process the form data and add it into the DB.
I suggest following a tutorial like:
WebMonkey |
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| 11-10-2005 12:09 PM |
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lordy
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O.P. RE: PHP/MySQL help
aaah that is excellent for adding stuff  thanks |
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| 11-10-2005 12:34 PM |
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Dempsey
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RE: PHP/MySQL help
no problem 
And about doing the search, you will be doing something similar, except instead of using INSERT, you will use SELECT, something like:
code:
SELECT dvdName, dvdYear (etc etc) FROM TableName WHERE dvdName LIKE `%searchTerms%` ORDER BY dvdName ASC
Where dvdName, dvdYear (etc, etc) is the field list you want to return, TableName is the name of the table you are searching in and searchTerms is from the textbox you search in. |
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| 11-10-2005 12:37 PM |
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-dt-
Scripting Contest Winner
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RE: PHP/MySQL help
also remember when using a unknown varible (from a form or something) in a sql query you should escape it with
code:
mysql_real_escape_string();
![[Image: dt2.0v2.png]](http://thedt.net/img/dt2.0v2.png) Happy Birthday, WDZ |
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| 11-10-2005 01:00 PM |
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lordy
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O.P. RE: PHP/MySQL help
well, so far i have this:
code:
<html>
<body>
<?php
$db = mysql_connect("127.0.0.1", "root");
mysql_select_db("movie_library",$db);
$_POST = array_map("mysql_escape_string",$_POST);
if (isset($_POST['dvd_title']))
{
//Form has been submitted
$dvd_title = $_POST['dvd_title'];
$dvd_director = $_POST['dvd_director'];
$dvd_classification = $_POST['dvd_classification'];
$dvd_actors = $_POST['dvd_actors'];
$dvd_genre = $_POST['dvd_genre'];
$dvd_year = $_POST['dvd_year'];
$dvd_length = $_POST['dvd_length'];
//insert to db
$sql = "INSERT into movies (dvd_title,dvd_director,dvd_classification,dvd_actors,dvd_genre,dvd_year,dvd_length) VALUES ('$dvd_title','$dvd_director','$dvd_classification','$dvd_actors','$dvd_genre','$dvd_year','$dvd_length')";
$result = mysql_query($db,$sql);
}
else{
?>
<form method="post" action="?">
DVD Title:<input type="Text" name="dvd_title"><br />
DVD Director:<input type="Text" name="dvd_director"><br />
DVD Classification:<input type="Text" name="dvd_classification"><br />
DVD Actors:<input type="Text" name="dvd_actors"><br />
DVD Genre:<input type="Text" name="dvd_genre"><br />
DVD Year:<input type="Text" name="dvd_year"><br />
DVD Length:<input type="Text" name="dvd_length"><br />
<input type="Submit" name="submit" value="Sumbit">
<?php
}
mysql_close($db);
?>
</body>
</html>
when i enter the data, the page goes blank (which im pretty sure its meant to), but the data isnt entered into the MySQL database.
I've asked -dt- on MSN and he couldn't find an error, so its probably someone hugely obvious, or something frustratingly small.
This post was edited on 11-11-2005 at 12:30 PM by lordy.
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| 11-11-2005 12:27 PM |
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Dempsey
Scripting Contest Winner
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Posts: 2395
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RE: PHP/MySQL help
after code:
$result = mysql_query etc
add code:
if (!$result){die('Invalid query: ' . mysql_error() . "<br>SQL: " . $sql);}
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| 11-11-2005 12:45 PM |
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lordy
Senior Member
Posts: 853
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35 / /
Joined: Jul 2004
Status: Away
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O.P. RE: PHP/MySQL help
i just chucked in random characters and it came up with this:
Invalid query:
SQL: INSERT into movies (dvd_title,dvd_director,dvd_classification,dvd_actors,dvd_genre,dvd_year,dvd_length) VALUES ('fjidjjfids','jfiodjfdos','kf','jifojodf jgf9idf','jdioas','1425','162')
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| 11-11-2005 12:54 PM |
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WDZ
Former Admin
Posts: 7106
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Joined: Mar 2002
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RE: PHP/MySQL help
http://php.net/mysql_query
resource mysql_query ( string query [, resource link_identifier] )
You have your arguments in the wrong order...
mysql_query($db,$sql)
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| 11-11-2005 02:05 PM |
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lordy
Senior Member
Posts: 853
Reputation: 24
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Joined: Jul 2004
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O.P. RE: PHP/MySQL help
OMGZORS it works
THANK YOU WDZ
now the next thing is to make a search form but that doesnt matter right now
thank you so much |
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| 11-11-2005 10:03 PM |
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